‘init(start:end:)’ is deprecated: it will be removed in Swift 3. Use the ‘..<’ operator

var continousDigitsRange:Range<Int> = Range<Int>(start: 0, end: 0)

Since update to Xcode 7.3 (Swift 2.2) I got the following hint:

'init(start:end:)' is deprecated: it will be removed in Swift 3. Use the '..<' operator.

新方法：

let string = “Who A U” string.substringWithRange(Range(string.startIndex.advancedBy(0) ..< string.startIndex.advancedBy(2)))

i++ i–

苹果认为 i++ 和 ++i在代码中容易产生理解错误。所以取消了 自增、自减。
改为 i += 1, 或 i -= 1

for var i = 0; i < 4; i++

• for index in 0…3

• for index in 0 ..< 4

    //定义数组
    var array = [String]()	
    或者 
    let array = ["a", "b", "c", "d"]
  
    for str in array {
    	print("\(str)")
    }
  
    //如果是一个对象数组。比如一个Model -- Person.swift
    var array = [Person]()
    或者
    let array = [person1, person2, person3]
    for person in array {
    	print("\(person.name)")
    }